# Coching, Mae - Asynch Day 4 - Game?
# I used most of Reaction_Time from Mission 10.
# User has a health of 1000, which is decreased by their reaction time.
# Score is the number of times they press button a before their health is gone.
# TODO for next time: Make a function so player has option to play again.

from codex import *
import time
import random

def wait_button():
    # Wait for Button A.
    while True:
        if buttons.was_pressed(BTN_A):
            break

total_time = 1000
presses = 0

while total_time >= 0:
    display.print("Press Button A")
    wait_button()

    display.clear()

    #All pixels off
    pixels.set([BLACK, BLACK, BLACK, BLACK])

    #Display countdown
    display.print("3", scale = 5)
    time.sleep(0.2)
    display.print("2", scale = 5)
    time.sleep(0.2)
    display.print("1", scale = 5)
    time.sleep(0.2)
    display.clear()

    ms = random.randrange(1000, 3000)
    delay_time = ms / 1000
    time.sleep(delay_time)

    # Reset button
    buttons.was_pressed(BTN_A)

    # Lights on
    pixels.set([GREEN, GREEN, GREEN, GREEN])

    # Mark time while awaiting reaction
    start_time = time.ticks_ms()
    wait_button()
    end_time = time.ticks_ms()

    reaction_time = time.ticks_diff(end_time, start_time)

    total_time = total_time - reaction_time
    presses = presses + 1

    display.print("Reaction time:")
    display.print(str(reaction_time) + " milliseconds")
    display.print("")
    display.print("Health: " + str(total_time))
    display.print("")
    display.print("Score: " + str(presses))
    display.print("")
    time.sleep(1)

display.clear()
display.print("Game Over!")
display.print("")
display.print("Score: " + str(presses))
display.print("")

# TODO fix the following so user can keep playing
# display.print("Press Button A to \nplay again")
# display.print("")
# wait_button()
# total_time = 1000
# presses = 0


repeat = 0
while repeat < 3:
    pixels.set([RED, GREEN, RED, GREEN])
    time.sleep(0.2)
    pixels.set([GREEN, RED, GREEN, RED])
    time.sleep(0.2)
    repeat = repeat + 1